Answer :
Answer:
3 x 10^18 kg
Explanation:
Time period, T = 3 days = 86400 x 3 = 259200 seconds
r = 7 x 10^5 m
Let M be the mass of planet
Use the formula of time period of satellite
[tex]T = 2\pi \sqrt{\frac{r}{GM}}[/tex]
Where, G be the universal gravitational constant.
[tex]M=\frac{4\pi ^{2}r^{3}}{GT^{2}}[/tex]
By substituting the values
[tex]M=\frac{4\times 3.14 \times 3.14\times \left ( 7\times 10^{5} \right )^{3}}{6.67\times 10^{-11}\times 259200\times 259200}[/tex]
M = 3 x 10^18 kg
Thus , the mass of planet is 3 x 10^18 kg.