Answer :
After solving the expression [tex]\frac{3y-2}{3}+\frac{2y+3}{3}=\frac{y+7}{6}[/tex] the value of y is [tex]y=\frac{5}{9}[/tex]
Step-by-step explanation:
We need to solve the expression [tex]\frac{3y-2}{3}+\frac{2y+3}{3}=\frac{y+7}{6}[/tex] to find value of y
Solving:
[tex]\frac{3y-2}{3}+\frac{2y+3}{3}=\frac{y+7}{6}[/tex]
Taking LCM of 3,3 and 6 is 6
Multiply all terms by 6
[tex]\frac{3y-2}{3}*6+\frac{2y+3}{3}*6=\frac{y+7}{6}*6\\(3y-2)*2+(2y+3)*2=y+7[/tex]
Simplifying:
[tex]6y-4+4y+6=y+7\\[/tex]
Combining like terms:
[tex]6y+4y+6-4=y+7\\10y+2=y+7[/tex]
Simplifying to find value of y:
[tex]10y-y=7-2\\9y=5\\y=\frac{5}{9}[/tex]
So, after solving the expression [tex]\frac{3y-2}{3}+\frac{2y+3}{3}=\frac{y+7}{6}[/tex] the value of y is [tex]y=\frac{5}{9}[/tex]
Keywords: Solving Fractions
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