Answer :

Step-by-step explanation:

[tex]1 \div (x - 2) + 2 < 0 [/tex]

[tex](1 + 2x - 4) \div ( x- 2) < 0[/tex]

[tex](2x - 3) \div (x - 2) < 0[/tex]

Hence

You have to put:

[tex]2x - 3 > 0[/tex]

And

[tex]x - 2 > 0[/tex]

Which results in:

[tex]x > 3 \div 2[/tex]

And

[tex]x > 2[/tex]

The solution is:

[tex]3 \div 2 < x < 2[/tex]

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