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A motorbike is travelling with a velocity of 3m/s. It accelerates at a rate of 9.3m/s for 1.8s. Calculate the distance it travels in this time​

Answer :

ReimannZeta

Explanation:

Consider the kinematic equation,

[tex]x = vt + \frac{1}{2} a {t}^{2} [/tex]

where x is the distance traveled, v is the initial velocity, a is the acceleration and t is time. By plugging in known values and solving for x,

[tex]x = 3(1.8) + \frac{1}{2} (9.3) {1.8}^{2} [/tex]

through simple algebra we get

[tex]x = 20.466[/tex]

where this is the distance traveled in meters.

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