What is the equation of the line, in point-slope form, that passes through the given point and has the given slope? Point (11, 3) slope: 9

y - 3 = 9(x + 11)

y - 3 = 9(x - 11)

y - 3 = -9(x - 11)

y - 11 = 9(x - 3)


Solve the equation or formula for the indicated variable
s=6r^3t, for t

Answer :

Answer:

OPTION B

Step-by-step explanation:

When a point on a line and the slope of the line are given the equation of the line is determined using the slope one- point form

                          [tex]$ (y - y_1) = m(x - x_1) $[/tex]

where, m = slope of the line

and [tex]$ (x_1,y_1) $[/tex] is the point passing through it.

Here [tex]$ (x_1,y_1) = (11,3) $[/tex] and [tex]$ m = 9 $[/tex].

Substituting in the formula we have: [tex]$ (y - 3) = 9(x - 11) $[/tex]

This is OPTION B. Hence, the answer.

Answer:

option b

Step-by-step explanation:

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