Answer :
Answer:
Option D) x = −4.41, −1.59
Step-by-step explanation:
We are given the following expression in the question:
[tex]2(x + 3)^2 - 4 = 0[/tex]
Solving the above expression, we get:
[tex]2(x + 3)^2 - 4 = 0\\2(x^2+9+6x)-4=0\\\text{Identity: }(a+b)^2 = a^2 + b^2 + 2ab\\2x^2+18+12x-4=0\\2x^2+12x+14=0\\\text{Using the quadratic formula:}\\ax^2 + bx +_ c = 0\\\\x = \displaystyle\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\text{Puting a = 2, b = 12, c = 14}\\\\x = \displaystyle\frac{-12\pm \sqrt{(12)^2-4(2)(14)}}{2(2)}\\\\x = \frac{-12 \pm 5.65}{4}\\\\x = \frac{-12 + 5.65}{4}, \frac{-12-5.65}{4} = -1.5875, -4.4125 \approx -1.59, -4.14[/tex]
