Answer:
A) 2H₂ + O₂ → 2H₂O
B) H₂O is the limiting reagent.
C) The maximum amount of H₂O formed = 198 grams.
Explanation:
A)
The balanced chemical equation for formation of water is
2H₂ + O₂ → 2H₂O.
B)
∵ For 2 moles of H₂, 1 mole of O₂ is required and forming 2 moles of H₂O,
⇒ When 11 moles of each reagent is taken, then H₂ gets completely consumed and 5.5 moles of O₂ which forms 11 moles of H₂O. and leaving 5.5 moles of O₂ unreacted.
We know that Limiting reagent is the one which gets completely consumed.
∴ H₂ is the limiting reagent.
C)
From the chemical equation, 4grams of H₂(2moles) reacts with 32grams of O₂(1mole) to form 36grams of H₂O(2moles).
So, for 11 moles of reactants, the maximum amount of H₂O formed by complete 11 moles consumption of H₂ = (11÷2)moles × 36grams = 198 grams