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An intergalactic rock star bangs his drum every 1.50 s. A person on earth measures that the time between beats is 2.70 s. How fast is the rock star moving relative to the earth?

Answer :

Answer:

v = 83.1 % of speed of light

Explanation:

given,

T_e is the earth time = 2.7 s

T_s is the ship time = 1.5 s

we know,

[tex]T_s = T_e \times \gamma[/tex]

where c is the speed of light

v is the speed of the rock star moving

[tex]T_s = T_e\times \sqrt{1-\dfrac{v^2}{c^2}}[/tex]

[tex]1.5= 2.7\times \sqrt{1-\dfrac{v^2}{c^2}}[/tex]

[tex] \sqrt{1-\dfrac{v^2}{c^2}} =0.556[/tex]

squaring both side

[tex] 1-\dfrac{v^2}{c^2}=0.3086[/tex]

[tex] v^2=0.6914c^2[/tex]

v = 0.831 c

v = 83.1 % of speed of light

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