Answer :
Answer:
False
Step-by-step explanation:
given that a race car driver tested his car for time from 0 to 60 mph, and in 20 tests obtained an average of 4.85 seconds with a standard deviation of 1.47 seconds.
Sample size n = 20
since population standard deviation is not known, we can use t critical value for finding out the confidence interval
df=19
t critical = 2.045
Margin of error = [tex]2.045*\frac{s}{\sqrt{n} } \\=2.045*\frac{1.47}{\sqrt{20} } \\=0.6722[/tex]
conidence interval = Mean±Margin of error
= [tex](4.85-0.6722, 4.85+0.6722)\\= (4.1778, 5.5222)[/tex]
The given confidence interval is (4.52, 5.18)
Hence the statement is false.