Answer :
Answer:
Explanation:
The rms velocity of gas molecules is proportional to square root of absolute temperature , that is
rms velocity ∝ √T
V₁ / V₂ = [tex]\sqrt{\frac{T_1}{T_2} }[/tex]
T₁ = 10°C = 10 + 273
= 283
T₂ = ?
Substituting the given values
( 1/2 )² = 283 / T₂
T₂ = 283 X 4
= 1132 K
= 1132 - 273
= 859°c
Answer:
T2= 1132-273= 859°C
Explanation:
The root mean velocity of a molecule is given by
[tex]V_{rsm}=\sqrt{\frac{3RT}{M_0} }[/tex]
R= gas constant
T= temperature of the gas
Mo= molecular weight of the gas
⇒V_{rsm}∝√T
⇒[tex]\frac{V{rsm}}{2V_{rsm}} =\sqrt{\frac{T_0}{T_2} }[/tex]
T_0= 273+10=283K
[tex]\frac{V{rsm}}{2V_{rsm}} =\sqrt{\frac{283}{T_2} }[/tex]
solving we T2= 1132 K
therefore T2= 1132-273= 859°C