Answer :
Answer:
The (minimum) thickness of the oil slick is 325 nm.
Explanation:
Let the (minimum) thickness of the oil slick = [tex]t_{o}[/tex]
Therefore:
2[tex]t_{o}[/tex] = ([tex]m_{red}[/tex]+[tex]\frac{1}{2}[/tex])*λ[tex]_{red}[/tex]/[tex]n_{o}[/tex] (1)
similarly,
2[tex]t_{o}[/tex]=([tex]m_{violet}+\frac{1}{2}[/tex])*λ[tex]_{violet}[/tex]/[tex]n_{o}[/tex] (2)
Thus, equation 1 = equation 2
([tex]m_{red}[/tex]+[tex]\frac{1}{2})[/tex]*λ[tex]_{red} /n_{o}[/tex] = ([tex]m_{violet}+\frac{1}{2})[/tex]*λ[tex]_{violet}/n_{o}[/tex]
Where:
λ[tex]_{red} = 650 nm[/tex]
λ[tex]_{violet} = 390 nm[/tex]
[tex]n_{o} = 1.5[/tex]
Therefore:
[tex]\frac{2m_{violet}+1 }{2n_{red}+1 }[/tex]=650/390=5/3
This shows that,
[tex]m_{violet}[/tex]=2
[tex]m_{red}[/tex]=1
Thus, using equation 2
[tex]t_{o}[/tex]=[tex]\frac{5*390}{2*2*1.5} =325 nm[/tex]