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You are told that a basketball player spins the ball on his finger with an angular acceleration of 118 rad sa 50% Part (a) What is the ball's final angular speed in radians per second, if the ball starts from rest and the acceleration lasts 3.4 s?

Answer :

Manetho

Answer:

ω = 401.2 rad/sec

Explanation:

we know that in a circular motion

[tex]\omega= \omega_0+\alpha t[/tex]

ω= final angular velocity

ω0=  initial angular velocity

α=  angular aceleration

t= time

Given ω0= 0, [tex]\alpha= 118 rad/sec^2[/tex] and t=3.4 sec

to find final angular velocity that is ω

[tex]\omega= 0+118\times3.4[/tex]

⇒ω = 401.2 rad/sec

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