Answer:
Explanation:
Given data:
Number of moles of He = n1= 1.35 mol
Number of moles of Ne = n2= 2.50 mol
Number of moles of Ar =n3= 2.30 mol
Total pressure = 2110 mmHg
Partial pressure of each component = ?
Solution:
Total number of moles = 1.35 + 2.50 mol + 2.30 mol
Total number of moles = 6.15 mol
P(He) = [ n₁/ nt ] P(total)
P(He) = [ 1.35 / 6.15 ] × 2110 mmHg
P(He) = [ 0.23 ] × 2110 mmHg
P(He) = 485.3 mmHg
P(Ne) = [ n₂/ nt ] P(total)
P(Ne) = [ 2.50/ 6.15 ] × 2110 mmHg
P(Ne) = 0.41 × 2110 mmHg
P(Ne) = 865.1 mmHg
P(Ar) = [ n₃/ nt ] P(total)
P(Ar) = [ 2.30/6.15 ]× 2110 mmHg
P(Ar) = [ 0.37 ]× 2110 mmHg
P(Ar) = 780.7 mmHg
