Answer:
[tex]A(\frac{\sqrt{3} }{2} ,\frac{1}{3})\\ \\and\\\\B( 1, 1)[/tex]
Point A {√3 /2 ,1 /3}
Point B { 1, 1}
could not be the points on the unit circle.
Step-by-step explanation:
Unit circle :
A circle having a radius of one unit is called the unit circle.
Standard equation of circle given by
x² + y² = r²
r = radius of
∴ x² + y² = 1²
∴ x² + y² = 1
∴ [tex]A(\frac{\sqrt{3} }{2} ,\frac{1}{3})\\ \\and\\\\B( 1, 1)[/tex]
Points are not on the unit circle as on substituting this x and y values
in the above equation we get
Left hand side ≠ Right-hand side
∴ [tex]A(\frac{\sqrt{3} }{2} ,\frac{1}{3})\\ \\and\\\\B( 1, 1)[/tex]
could not be the points on the unit circle.