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A businessperson took a small airplane for a quick flight up the coast for a lunch meeting and then returned home. The plane flew a total of 4 hours, and each way the trip was 200 miles. What was the speed of the wind that affected the plane, which was flying at a speed of 120mph? Round your answer to the nearest whole number.

Answer :

Answer:

Speed of the wind is 48.989 mph

Explanation:

We have given each trip is of 200 miles

So total distance = 200 +200 = 400 miles

Speed of the airplane = 120 mph

Let the speed of the wind = x mph

So the speed of the airplane with wind = 120+x

So time taken by airplane with wind = [tex]\frac{200}{120+x}[/tex]

Speed of the airplane against the wind = 120 - x

So time taken by the airplane against the wind [tex]=\frac{200}{120-x}[/tex]

Total time is given as t= 4 hour

So [tex]\frac{200}{120+x}+\frac{200}{120-x}=4[/tex]

[tex]\frac{200(120-x)+200(120+x)}{(120+x)(120-x)}=4[/tex]

[tex]48000=57600-4x^2[/tex]

[tex]4x^2=9600[/tex]

x = 48.989 mph

Cinthiaverdin8987

Answer:

Explanation:

  Type                           Distance             Rate         Time

Headwind 200 120-r   200/120-r

Tailwind     200  120 - r  200/120 - r

We know the times add to 4, so we write the equation:

200/120−r +   200/120 + r = 4  

We multiply both sides by the LCD and simplify to get:

(120−r)(120+r) ((200/120 -r ) + 200/120+r) = 4(120 -r) (120 +r)

200(120−r)+200(120+r)=4(120−r)(120+r)

Factor the 200 and simplify inside the parentheses to find:

200(120−r+120+r)=4(1202−r2)

200(240)=4(1202−r2)

200(60)=120^2−r^2

12,000=14,400−r^2

−2,400= −r^2

49 ≈ r

The speed of the wind is 49mph.

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