Answer :

Answer:

The value of x for the expression is 2

Step-by-step explanation:

Given algebraic expression as :

[tex]\frac{1}{2}[/tex](4 + 6 x ) = [tex]\frac{1}{3}[/tex] x + [tex]\frac{2}{3}[/tex] ( x + 9 )

Now, solving the given expression

Or, [tex]\frac{1}{2}[/tex] × 4 + [tex]\frac{1}{2}[/tex] × 6 x = [tex]\frac{1}{3}[/tex] x + [tex]\frac{2}{3}[/tex] x + [tex]\frac{2}{3}[/tex] × 9

Or,  [tex]\frac{4}{2}[/tex]  + [tex]\frac{6}{2}[/tex] × x = [tex]\frac{1}{3}[/tex] x + [tex]\frac{2}{3}[/tex] x + [tex]\frac{18}{3}[/tex]

or, 2 + 3 × x = [tex]\frac{x}{3}[/tex] + [tex]\frac{2 x}{3}[/tex]  + 6

or, 2 + 3 × x =  [tex]\frac{2 x + x}{3}[/tex]  + 6

or, 2 + 3 × x = [tex]\frac{3 x}{3}[/tex]  + 6

Or, 2 + 3 × x = x + 6

or, 3 x - x =  6 - 2

Or, 2 x = 4

∴  x = [tex]\frac{4}{2}[/tex]

I.e x = 2

Hence The value of x for the expression is 2 Answer

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