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For the first 30 km, the bicyclist rode with a speed of v km/hour. For the remaining 17 km he rode with a speed which was 2 km/hour greater than his original speed. How much time did the bicyclist spend on the entire trip? Let t be the time (in hours), and find t if:

a) v=15
b) v=18

Answer :

The value of t is:

a) when v = 15 then t = 3 hours

b) when v = 18 then t = 2.52 hours

Solution:

The relation between speed and time taken is given as:

[tex]\text {time taken}=\frac{\text {distance}}{\text {speed}}[/tex]

It is given that for first 30 km, the speed of bicyclist is v km/hour

Time taken to cover first 30 km is given by:

[tex]t_1 = \frac{v}{30}[/tex]

For next 17 km the speed of bicyclist is 2 km/hour greater than his original speed

so the speed to cover next 17 km = v + 2

Time taken to cover next 17 km is given by:

[tex]t_{2} =\frac{17}{v+2}[/tex]

Now total time t spent by the bicyclist to cover entire trip is given by

[tex]t=t_{1} +t_{2}\\\\t=\frac{30}{v} +\frac{17}{v+2}[/tex]  ---- eqn 1

We have to find value of "t" for a) v = 15 and b) v = 18

a) value of t when v = 15

Substitute v = 15 in eqn 1

[tex]t=\frac{30}{v}+\frac{17}{v+2}=\frac{30}{15}+\frac{17}{15+2}[/tex]

t = 2 + 1 = 3

So t = 3 hours

b) value of t when v = 18

[tex]\begin{array}{l}{t=\frac{30}{v}+\frac{17}{v+2}=\frac{30}{18}+\frac{17}{18+2}=1.67+0.85} \\\\ {t=2.52}\end{array}[/tex]

Thus t = 2.52 hours

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