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You push a piece of wood under the surface of a swimming pool. After it is completely submerged, you keep pushing it deeper and deeper. As you do this, what will happen to the buoyant force on it? Will the force keep increasing, stay the same, or decrease? Why?

Answer :

Answer:Same

Explanation:

If we keep on pushing the wooden block the buoyant force on it will remain same as it depends upon the volume of object submerged in liquid and density of liquid .

Buoyant force is given by

[tex]F_b=\rho _{liquid}Vg[/tex]

where [tex]F_b=[/tex]buoyant force

it is independent of depth of object from free surface.

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