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A typical person's eye is 2.5 cm in diameter and has a near point (the closest an object can be and still be seen in focus) of 25 cm, and a far point (the farthest an object can be and still be in focus) of infinity.

1) What is the minimum effective focal length of the focusing mechanism (lens plus cornea) of the typical eye?
2) What is the maximum effective focal length of the focusing mechanism (lens plus cornea) of the typical eye?

Answer :

boffeemadrid

Answer:

2.27 cm

2.5 cm

Explanation:

u = Object distance =  25 cm

v = Image distance = 2.5 cm

f = Focal length

Lens Equation

[tex]\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}=\frac{1}{25}+\frac{1}{2.5}\\\Rightarrow \frac{1}{f}=\frac{11}{25}\\\Rightarrow f=\frac{25}{11}=2.27\ cm[/tex]

The minimum effective focal length of the focusing mechanism of the typical eye is 2.27 cm

when [tex]u=\infty[/tex]

[tex]\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}=\frac{1}{\infty}+\frac{1}{2.5}\\\Rightarrow \frac{1}{f}=\frac{1}{2.5}\\\Rightarrow f=\frac{2.5}{1}=2.5\ cm[/tex]

The maximum effective focal length of the focusing mechanism of the typical eye is 2.5 cm

adefioyelaoye
  • The minimum effective focal length of the focusing mechanism (lens plus cornea) of the typical eye is 2.27cm.
  • The maximum effective focal length of the focusing mechanism (lens plus cornea) of the typical eye is 2.5cm.

What is Focal length?

This is defined as a measure of how strongly the system converges or diverges light.

Parameters

u = Object distance =  25 cm

v = Image distance = 2.5 cm

f = Focal length

1/f = 1/u + 1/v

1/f = 1/25 + 1/25

1/f = 11/25

f = 25/11 = 2.27cm

When u is at ∞

1/f = 1/u + 1/v

1/f = 1/∞ + 1/2.5

1/f = 1/2.5

f = 2.5cm.

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