Answer :
Answer:
The minimum coefficient of friction is 0.544
Solution:
As per the question:
Radius of the curve, R = 48 m
Speed of the car, v = 16 m/s
To calculate the minimum coefficient of static friction:
The centrifugal force on the box is in the outward direction and is given by:
[tex]F_{c} = \frac{mv^{2}}{R}[/tex]
[tex]f_{s} = \mu_{s}mg[/tex]
where
[tex]\mu_{s}[/tex] = coefficient of static friction
The net force on the box is zero, since, the box is stationary and is given by:
[tex]F_{net} = f_{s} - F_{c}[/tex]
[tex]0 = f_{s} - F_{c}[/tex]
[tex]\mu_{s}mg = \frac{mv^{2}}{R}[/tex]
[tex]\mu_{s} = \frac{v^{2}}{gR}[/tex]
[tex]\mu_{s} = \frac{16^{2}}{9.8\times 48} = 0.544[/tex]