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A spaceship of mass 2.10×106 kg is cruising at a speed of 4.20×106 m/s when the antimatter reactor fails, blowing the ship into three pieces. One section, having a mass of 5.20×105 kg , is blown straight backward with a speed of 1.80×106 m/s . A second piece, with mass 7.80×105 kg , continues forward at 1.30×106 m/s .

Answer :

Answer:complete question

What is the velocity of the third piece assume the initial velocity is positive

Answer is -9.75*10^4m/s

Explanation:

Let M be the mass of spaceship before breaking=2.10*10^6kg

V is the Initial speed of the spaceship=4.2*10^6m/s

M1=mass of the first piece=5.2*10^5kg

V1 first piece velocity =-1.80*10^6m/s

M2 second piece mass =7.8*10^5kg

V2 second piece velocity=1.30*10^6m/s

M3=M-M1-M2

=8.0*10^5kg

Also v3 is the velocity of the third piece.

Hence from linear momentum formulae

MV=M1V1+M2V2+M3V3

8.82*10^6=-9.36*10^11+1.014*10^12+M3V3

M3v3=-7.79*10^10

V3=-9.75*10^4m/s in the backward direction

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