Answer :
Answer:
Therefore,
[tex]\textrm{Perimeter of rectangle}=14\ cm[/tex]
Step-by-step explanation:
Given:
Rectangle ABCD
vertices of the rectangle:
A(-2,2),
B(3,2),C(3,4),and D(-2,4),
Let,
Length of Rectangle be AB and Width be BC
To Find:
Perimeter of rectangle ABCD = ?
Solution:
We Know ,
[tex]\textrm{Perimeter of rectangle}=2(Length + Width)[/tex]
Lets find length and width by Distance Formula,
[tex]l(AB) = \sqrt{((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} )}[/tex]
On substituting the values we get
[tex]l(AB) = \sqrt{((3+2)^{2}+(2-2)^{2} )}[/tex]
[tex]l(AB) = \sqrt{((5)^{2}}=5\ units[/tex]
Similarly,
[tex]l(BC) = \sqrt{((3-3)^{2}+(4-2)^{2} )}[/tex]
[tex]l(BC) = \sqrt{4}=2\ units[/tex]
Now substituting AB and BC in Perimeter Formula we get
[tex]\textrm{Perimeter of rectangle}=2(AB + BC)=2(5+2)=2\times 7=14\ cm[/tex]
Therefore,
[tex]\textrm{Perimeter of rectangle}=14\ cm[/tex]
Note Here Vetex A is wrong the correct on is A(-2 ,2)