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A farmer connects a pipe of internal diameter 20 cm from a canal into a cylindrical tank in his field which is 10 m in diameter and 2 m deep. If water flows through the pipe at the rate of 3 km/hr, in how much time will the tank be filled

Answer :

nandhini123

Answer:

It takes 100 minutes to fill the tank.

Step-by-step explanation:

Let the length of the  pipe used for filling the tank be h

Then

Volume of the  pipe =  volume of the tank

Step 1: Finding the volume of the pipe

The pipe is in cylindrical form with height h and diameter 20m

The volume of the pipe  = [tex]\pi r^2h[/tex]

Where r is the radius of the pipe

r = [tex]\frac{diameter}{2}[/tex]

r = [tex]\frac{20}{2}[/tex]

r = 10cm = [tex]\frac{1}{10}[/tex]

The volume of the pipe

=> [tex]\pi (\frac{1}{10})^2 h[/tex]

=> [tex]\frac{1}{100}\pi h[/tex]

=> [tex]\frac{\pi h}{100}[/tex]-----------------------------------(1)

Step 2: Finding the volume of the tank

The volume of the tank = [tex]\pi r^2h[/tex]

Where r is the radius of the tank

r = [tex]\frac{diameter}{2}[/tex]

r = [tex]\frac{10}{2}[/tex]

r = 5

The volume of the pipe

=> [tex](\pi )(5)^2 (2)[/tex]

=> [tex]50 \pi[/tex]-------------------------------------(2)

Equating (1) and (2)

[tex]\frac{\pi h}{100}[/tex] =  [tex]50 \pi[/tex]

[tex]\frac{h}{100}[/tex] =  50

h =  50 X 100

h =5000m =5km

The flow rate of water through the pipe  = 3 km/hr

time taken to travel 3 km  = 1 hours

so time taken 1 km  = [tex]\frac{1}{3}[/tex] hours

To Travel 5 km

=> [tex]5 \times \frac{1}{3}[/tex] hours

=> [tex]\frac{5}{3}[/tex] hours

converting into minutes

=> [tex]\frac{5}{3} \times 60[/tex]

=>[tex]\frac{300}{3}[/tex]

=> 100 minutes

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