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A 10-7 is performed on a culture of bacteria in order to perform viable plate counts. From the dilution, *0.1 mL* of solution is plated on solid media, and 66 colonies of bacteria grow on the plate. Assuming each colony came from a single bacterium, how many bacteria are in a single mL of the original culture?

Answer :

Answer:

[tex]66 * 10^8[/tex] CFU/mL

Explanation:

Given -

a) Number of colonies of bacteria is equal to [tex]66[/tex]

b) Total volume of the solution is equal to [tex]0.1[/tex] mL

c) Dilution factor is equal to [tex]10^{-7}[/tex]

As we know that

CFU/mL [tex]= \frac{N * DF}{V}[/tex]

Where N is the number of bacterial colonies, DF is the dilution factor and V is the volume

Substituting the given values in above equation, we get -

CFU/mL [tex]= \frac{66* 10^7}{0.1} \\= 66*10^8[/tex]

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