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write the equation of a line that is perpendicular to the given line and that passes through the given point y-2=-1/4(x+3);(-3,5)

Answer :

chau23
The answer is y=4x+17
Hope this would help!!!
${teks-lihat-gambar} chau23
grujan50

Answer:

Correct answer: y₁ = 4x + 17

Step-by-step explanation:

Given: Line l :  y= - 1/4 x + 5/4 and point named A(-3, 5)

Slope (gradient) of this line is s = - 1/4

The line we are looking for l₁ is perpendicular to the given l which means

l₁ ⊥ l => s₁ = - 1/ s  => s₁ = 4

The equation of line through one point is: y - ya = s₁(x - xa)

y - 5 = 4 (x + 3) => y₁ = 4x + 12 + 5 => y₁ = 4x + 17

God is with you!!!

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