Answer:
Option c) is correct.
That is x-5y=12 and 3x+2y=-15 are the system of linear equations satisfies the point (-3,3) so this is the solution.
Step-by-step explanation:
To verify that which system of linear equations having the solution (-3,-3)
Let [tex]x-5y=12\hfill (1)[/tex]
and [tex]3x+2y=-15\hfill (2)[/tex]
To solve it we have to use elimination method
First multiply the equation(1) into 3 we get
[tex]3x-15y=36\hfill (3)[/tex]
Now subtracting the equations (2)and (3) the signs may vary in the second equation we get
[tex]3x-15y=36[/tex]
[tex]-3x-2y=+15[/tex]
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[tex]-17y=51[/tex]
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[tex]y=-\frac{51}{17}[/tex]
[tex]y=-3[/tex]
Now substitue the value y=-3 in equation (1) we get
[tex]x-5y=12[/tex]
[tex]x-5(-3)=12[/tex]
[tex]x=12-15[/tex]
Therefore x=-3
Therefore the solution is (-3,-3)
Therefore Option c) is correct.
That is x-5y=12 and 3x+2y=-15 are the system of linear equations satisfies the point (-3,3) so the solution is (-3,-3).