Answer :
Answer:
[tex]H_2SO_4_{(aq)}+2LiOH_{(aq)}\rightarrow H_2O_{(l)}+Li_2SO_4_{(aq)}[/tex]
[tex]2H^+_{(aq)}+2OH^{-}\rightarrow H_2O_{(l)}[/tex]
Explanation:
Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.
Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.
Only the species which are present in aqueous state dissociate.
Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.
(a)
The balanced molecular equation will be,
[tex]H_2SO_4_{(aq)}+2LiOH_{(aq)}\rightarrow H_2O_{(l)}+Li_2SO_4_{(aq)}[/tex]
The complete ionic equation in separated aqueous solution will be,
[tex]2H^+_{(aq)}+SO_4^-_{(aq)}+2Li^+_{(aq)}+2OH^{-}_{(aq)}\rightarrow H_2O_{(l)}+2Li^+_{(aq)}+SO_4^-_{(aq)}[/tex]
In this equation the species present are, [tex]Li^+\text{ and }SO_4^-[/tex] are the spectator ions.
Hence, the net ionic equation contains specie is
[tex]2H^+_{(aq)}+2OH^{-}\rightarrow H_2O_{(l)}[/tex]