Answer :
Answer:
Explanation:
Given
velocity of antelope [tex]v=10 m/s[/tex]
antelope needs to cover a horizontal distance of 20 m
considering horizontal velocity antelope needs to cover 20 m in t sec which is given by
[tex]t=\frac{20}{10}=2 s[/tex]
i.e. in 2 sec antelope needs to jump and return to ground for zero vertical displacement
[tex]h=ut+\frac{1}{2}at^2[/tex]
h=vertical displacement
a=acceleration
t=time
for, [tex]h_{max}[/tex], t=1 s
[tex]h_{max}=0+\frac{1}{2}g(1)^2[/tex]
[tex]h_{max}=\frac{g}{2}[/tex]
[tex]h_{max}=4.9 m[/tex]