Factor each by factoring out the greatest common factor:
1. 10ab+5a
2. 3(????^3)ℎ−9(????^2)ℎ+12ℎ
3. 6(x^2)(y^3)+9x(y^4)+18y^5

Answer :

Answer:

1. Given expression,

[tex]10ab + 5a[/tex]

∵ 10ab = 2 × 5 × a × b,

5a = 5 × a

So, GCF(10ab, 5a) = 5a,

We can write,

[tex]10ab + 5a=5a\times 2b + 5a = 5a(2b+1)[/tex]

2. Given expression,

[tex]3(x^3)h-9(x^2)h+12h[/tex]

∵ 3(x³)h= 3 × x × x × x × h,

9(x²)h = 3 × 3 × x × x × h

12h = 2 × 2 × 3 × h

So, GCF(3(x³)h, 9(x²)h, 12h ) = 3h,

We can write,

[tex]3(x^3)h-9(x^2)h+12h=3h\times x^3 - 3h\times 3x^2+3h\times 4= 3h(x^3-3x^2+4)[/tex]

3. Given expression,

[tex]6(x^2)(y^3)+9x(y^4)+18y^5[/tex]

∵ 6(x²)(y³) = 2 × 3 × x × x × y × y × y,

[tex]9x(y^4)[/tex] = 3 × 3 × x × y × y × y × y

[tex]18y^5[/tex] = 2 × 3 × 3 × y × y × y × y × y

So, GCF([tex]6(x^2)(y^3),9x(y^4), 18y^5[/tex]) = 3y³,

We can write,

[tex]6(x^2)(y^3)+9x(y^4)+18y^5=3y^3\times 2x^2 + 3y^3\times 3xy+3y^3\times 6y^2 = 3y^3(2x^2+3xy+6y^2)[/tex]

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