Answer :
Answer:
y=-1 is the equation of the line
Step-by-step explanation:
x + 2y = 3 and
solve for x and y to get intersection point
multiply first equation by -2
[tex]-2x -4y = -6[/tex]
[tex]2x - 3y = 13[/tex]
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[tex]-7y=7[/tex]
y=-1
[tex]x + 2y = 3[/tex]
[tex]x + 2(-1)= 3[/tex]
[tex]x -2= 3[/tex]
x=5
intersection point is (5,-1)
(2, -1) and (5,-1)
[tex]slope = \frac{y_2-y_1}{x_2-x_1} =\frac{-1+1}{5-2} =0[/tex]
Slope = 0 (horizontal line)
So equation becomes y =y1 value
y=-1 is the equation of the line