Answer :
Answer:
sin(B) = 12/13
cos(B) = 5/13
tan(B) = 12/5
csc(B) = 13/12
sec(B) = 13/5
cot(B) = 5/12
Step-by-step explanation:
If ABC is a right triangle, assuming that ∠C = 90°, then the segment AB =13 is the hypotenuse and the other two sides are:
[tex]BC = 5\\AC = \sqrt{13^2 - 5^2}\\AC = 12[/tex]
The six trigonometric functions of angle B are:
[tex]sin(B) =\frac{AC}{AB}= \frac{12}{13}\\cos(B) = \frac{BC}{AB} =\frac{5}{13}\\tan(B) = \frac{AC}{BC} =\frac{12}{5}\\\csc(B) =\frac{1}{sin(B)}= \frac{13}{12}\\sec(B) = \frac{1}{cos(B)} =\frac{13}{5}\\cot(B) = \frac{1}{tan(B)} =\frac{5}{12}\\[/tex]