Answered

The molar heats of fusion and sublimation of molecular
iodineare 15.27 kJ/mol and 62.30 kJ/mol, respectively. Estimate the
molarheat of vaporization of liquid Iodine.

Answer :

Answer:

47.03 KJ/mol

Explanation:

given:

molar heat of fusion, Hfusion = 15.27 KJ/mol

molar heat of sublimation, Hsublime = 62.30 KJ/mol

molar heat of vaporisation, Hvaporise = ?

Hsublime = Hfusion + Hvaporise

Hvaporise = Hsublime - Hfusion

Hence, the molar heat of vaporization of liquid iodine

= 62.30 - 15.27 = 47.03 KJ/mol

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