Answered

A pocket of gas is discovered in a deep drilling operation.The
gas has a temperature of 480 degrees celsius and is at a pressure
of 12.8 atm. What volume of gas is required toprovide 18.01L of gas
at the surface where the conditions are 22degrees celsius and
1.00atm?

Answer :

Answer : The volume of gas required to provide 18.01L of gas  at the surface is, 3.6 L

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]

where,

[tex]P_1[/tex] = initial pressure of gas = 12.8 atm

[tex]P_2[/tex] = final pressure of gas = 1.0 atm

[tex]V_1[/tex] = initial volume of gas = ?

[tex]V_2[/tex] = final volume of gas = 18.01 L

[tex]T_1[/tex] = initial temperature of gas = [tex]480^oC=273+480=753K[/tex]

[tex]T_2[/tex] = final temperature of gas = [tex]22^oC=273+22=295K[/tex]

Now put all the given values in the above equation, we get:

[tex]\frac{12.8atm\times V_1}{753K}=\frac{1.0atm\times 18.01L}{295K}[/tex]

[tex]V_1=3.59L\approx 3.6L[/tex]

Therefore, the volume of gas required to provide 18.01L of gas  at the surface is, 3.6 L

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