Answer :
The cost of one child ticket is $4 and cost of adult ticket is $7.
Step-by-step explanation:
Let,
Cost of one child ticket = x
Cost of one adult ticket = y
According to given statement;
9x+2y=50 Eqn 1
10x+3y=61 Eqn 2
Multiplying Eqn 1 by 3
[tex]3(9x+2y=50)\\27x+6y=150\ \ \ Eqn\ 3[/tex]
Multiplying Eqn 2 by 2
[tex]2(10x+3y=61)\\20x+6y=122\ \ \ Eqn\ 4[/tex]
Subtracting Eqn 4 from Eqn 3
[tex](27x+6y)-(20x+6y)=150-122\\27x+6y-20x-6y=28\\7x=28[/tex]
Dividing both sides by 7
[tex]\frac{7x}{7}=\frac{28}{7}\\x=4[/tex]
Putting x=4 in Eqn 1
[tex]9(4)+2y=50\\36+2y=50\\2y=50-36\\2y=14\\[/tex]
Dividing both sides by 2
[tex]\frac{2y}{2}=\frac{14}{2}\\y=7[/tex]
The cost of one child ticket is $4 and cost of adult ticket is $7.
Keywords: linear equation, elimination method
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