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A 12-kg piece of metal displaces 1.6 L of water when submerged. Part A Find its density. Express your answer to two significant figures and include the appropriate units.

Answer :

Answer:

ρ = 7500 kg/m³

Explanation:

Given that

mass ,m = 12 kg

Displace volume ,V= 1.6 L

We know that

1000 m ³ = 1 L

Therefore V= 0.0016 m ³

When metal piece is fully submerged

We know that

mass = Density x volume

[tex]m=\rho \times V[/tex]

Now by putting the values in the above equation

[tex]\rho=\dfrac{12}{0.0016}\ kg/m^3[/tex]

ρ = 7500 kg/m³

Therefore the density of the metal piece will be  7500 kg/m³.

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