19. A silver statue of Pooja is leaning against a wall. The top of her head
touches the wall at 40 feet. If the base of the statue is 9 feet away from the
wall, how tall is Pooja’s statue, in feet?

Answer :

luisejr77

Answer: [tex]41\ feet[/tex]

Step-by-step explanation:

You need to draw a right triangle.

Observe the right triangle attached, where "x" is the height in feet of Pooja’s statue.

You need to use the Pythagorean Theorem. This is:

[tex]a^2=b^2+c^2[/tex]

Where "a" is the hypotenuse and "b" and "c" are the legs of the right triangle.

In this case you can identify that:

[tex]a=x\\b=40\\c=9[/tex]

Therefore, you can substitute values into [tex]a^2=b^2+c^2[/tex]:

[tex]x^2=40^2+9^2[/tex]

Finally, you must solve for "x" in order to find its value.

You get that this is:

[tex]x=\sqrt{40^2+9^2}\\\\x=41[/tex]

${teks-lihat-gambar} luisejr77