Answer :
Answer:
There are 756.25 electrons present on each sphere.
Explanation:
Given that,
The force of repression between electrons, [tex]F=3.33\times 10^{-21}\ N[/tex]
Let the distance between charges, d = 0.2 m
The electric force of repulsion between the electrons is given by :
[tex]F=k\dfrac{q^2}{r^2}[/tex]
[tex]q=\sqrt{\dfrac{Fr^2}{k}}[/tex]
[tex]q=\sqrt{\dfrac{3.33\times 10^{-21}\times (0.2)^2}{9\times 10^9}}[/tex]
[tex]q=1.21\times 10^{-16}\ C[/tex]
Let n are the number of excess electrons present on each sphere. It can be calculated using quantization of charges. It is given by :
q = ne
[tex]n=\dfrac{q}{e}[/tex]
[tex]n=\dfrac{1.21\times 10^{-16}}{1.6\times 10^{-19}}[/tex]
n = 756.25 electrons
So, there are 756.25 electrons present on each sphere. Hence, this is the required solution.