Answer :
Answer:
(a) [tex]\omega=2.09*10^{5}\frac{rad}{s}[/tex]
(b) [tex]A_{max}=0.033m[/tex]
Explanation:
(a) The angular frequency is defined as:
[tex]\omega=2\pi f[/tex]
Here f is the frequency of the particle, which is inversely proportional to its period:
[tex]f=\frac{1}{T}[/tex]
Replacing, we have:
[tex]\omega=\frac{2\pi}{T}\\\omega=\frac{2\pi}{3*10^{-5}s}\\\omega=2.09*10^{5}\frac{rad}{s}[/tex]
(b) The maximum displacement is given by:
[tex]A_{max}=\frac{v_{max}}{\omega}\\A_{max}=\frac{7*10^3\frac{m}{s}}{2.09*10^5\frac{rad}{s}}\\A_{max}=0.033m[/tex]