Two curling stones collide on an ice rink. Stone 1 has a mass of 16 kg
and an initial velocity of 1.5 m/s to the north. Stone 2 was at rest
initially. The stones collide dead center, giving stone 2 a final velocity
of 0.69 m/s to the north.

Question

Today at 4:13 PM
Physics

Answered

Two curling stones collide on an ice rink. Stone 1 has a mass of 16 kg
and an initial velocity of 1.5 m/s to the north. Stone 2 was at rest
initially. The stones collide dead center, giving stone 2 a final velocity
of 0.69 m/s to the north.

Answer :

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jackfire3913 jackfire3913 · Answer 1 · 2025-03-25T16:19:39-04:00

jackfire3913 jackfire3913

Today at 4:19 PM

Answer:

53.57 kg or 54 kg

-.81 m/s

Explanation:

m2=[tex]\frac{v}{vf2} \\[/tex] (2m1) -m1

v1f= [tex](\frac{m1-m2}{m1+m2})v[/tex]

Answer Link

pstnonsonjoku pstnonsonjoku · Answer 2 · 2025-03-25T16:18:59-04:00

The final velocity of the first stone can be calculated as 2.3 m/s.

What is conservation of linear momentum?

The principle of the conservation of linear momentum states that the momentum before collision is equal to the momentum after collision.

Having said that;

m1u1 + m2u1 = m1v2 + m2v2

But we know that v2 is the same for the two bodies when they stick together.

Hence;

2(16 * 1.5) = (16 * v) + (16 * 0.69)

v = 48 - 11/16

v = 2.3 m/s

The final velocity of the first stone can be calculated as 2.3 m/s.

Learn more about velocity:https://brainly.com/question/1851822

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Two curling stones collide on an ice rink. Stone 1 has a mass of 16 kg and an initial velocity of 1.5 m/s to the north. Stone 2 was at rest initially. The stones collide dead center, giving stone 2 a final velocity of 0.69 m/s to the north.

Answer :

What is conservation of linear momentum?

Other Questions

Two curling stones collide on an ice rink. Stone 1 has a mass of 16 kg
and an initial velocity of 1.5 m/s to the north. Stone 2 was at rest
initially. The stones collide dead center, giving stone 2 a final velocity
of 0.69 m/s to the north.