Answer :
Answer:
The value of A is [tex](-\infty, 0) \cup(0, \infty)[/tex]
Step-by-step explanation:
Given:
[tex]V = A (t- 0.05t^2)[/tex]
When velocity V= 0
we have
[tex]A (t- 0.05t^2) = 0[/tex]
[tex](t- 0.05t^2) = 0[/tex]
[tex]t = 0.05t^2[/tex]
t =0 , t = [tex]\frac{1}{0.05}[/tex]
t = 0 , t = 20
So when we draw a graph,The resulting graph will be a quadratic graph.
[tex]\frac{dv}{dt} = A[1 - 0.1t][/tex]
[tex]\frac{dv}{dt} = 0[/tex]
t=10 sec
At t=10, the velocity will be
[tex]v(10) = [10 -0.05(10)^2][/tex]
[tex]v(10) = [10 -5][/tex]
[tex]v(10) = 5A[/tex]
But according to the question A is not dependent on t
So A can be any value other than zero