Answer :
Answer:
The net force acting on the otter along the incline is 13.96 N.
Explanation:
It is given that,
Mass of the otter, m = 2 kg
Distance covered by otter, d = 85 cm = 0.85 m
It takes 0.5 seconds.
We need to find the net force acts on the otter along the incline. If a is the acceleration of the otter. It can be calculated using second equation of motion as :
[tex]d=ut+\dfrac{1}{2}at^2[/tex]
Here, u = 0 (at rest)
[tex]d=\dfrac{1}{2}at^2[/tex]
[tex]a=\dfrac{2d}{t^2}[/tex]
[tex]a=\dfrac{2\times 0.85}{0.5^2}[/tex]
[tex]a=6.8\ m/s^2[/tex]
The net force acting on the otter along the incline is given by :
F = ma
[tex]F=2\ kg\times 6.8\ m/s^2[/tex]
F = 13.6 N
So, the net force acting on the otter along the incline is 13.96 N. Hence, this is the required solution.
Answer:
[tex]F=13.6\rm N[/tex] Force acts on the otter along the incline
Explanation:
Given information:
Incline length [tex]s=\rm 85cm=0.85m[/tex]
Time [tex]t=0.5\rm sec[/tex]
Mass of otter [tex]m=2\rm kg[/tex],
Initial velocity [tex]u=0[/tex] as otter is in rest
Muddy incline so we can assume surface as friction less
By use equation of motion,
[tex]s=ut+\frac{1}{2} a t^2[/tex]
[tex]s=ut+\frac{1}{2} a t^2=0\times t+\frac{1}{2}\times a\times t^2[/tex]
[tex]0.85=0+\frac{1}{2} a (0.5)^2\\\\a=\frac{2\times0.85}{0.5^2}=6.8\rm m/s^2[/tex]
The net force act on the otter is
[tex]F=ma[/tex]
[tex]F=2\rm kg\times6.8\rm m/s^2[/tex]
[tex]F=13.6\rm N[/tex]
Hence [tex]F=13.6\rm N[/tex] force acts on the otter along the incline
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