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The letters A, B, C, D, E, and F are written on six different ping pong balls and put into a bag. The letters H, I, J, and K are written on another four different ping pong balls and put into a second bag. Then the letters O, P, Q, R, S, T, and U are written on another seven different ping pong balls and put into a third bag. If one ping pong ball is randomly selected from each of the three bags, what is the probability that at least one vowel (A, E, I, O, U) is selected?

Answer :

pedrocarratore

Answer:

0.6429 or 64.29%

Step-by-step explanation:

The probability that at least one vowel is selected is 100% minus the probability that no vowel is selected. The probability that no vowels are selected for each pot are:

[tex]P_1 =\frac{4}{6}\\P_2 =\frac{3}{4}\\P_3=\frac{5}{7}[/tex]

The probability that at least one vowel is selected is:

[tex]P(V>0) = 1 - P(V=0)\\P(V>0) = \frac{4}{6}*\frac{3}{4}*\frac{5}{7}\\P(V>0) = 0.6429[/tex]

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