For what value of x is the function g(x)=x/1-x NOT defined?

The function is definately defined at x=0 but not x=1.
But its just one part of the coordinate (x,y).
If the value of y or f(x) is considered, you'll see that it is never possible to attain f(x)=0. In other terms (x,y)= (0,0) is not a defined point in the graph of the function because the graph doesnt pass through that point.
Now I hope you understood what I meant!
Conclusion- The above function is not defined at all points in the space having the abscissa or x=1 in the coordinate and also at ordinate or y=0 in the coordinate.nation:
The value of x for which the function g(x)=x/1-x is not defined is at x = 1.
A value of a function becomes not defined when the denominator of that function becomes zero.
The function is g(x)=x/1-x.
We can substitute the different values of x to find which makes the function not defined.
g(-1) = -1/1-(-1)
= -1/2
The function is defined.
g(0) = 0/1-0
= 0
The function is defined.
g(1) = 1/1-1
= 1/0 = not defined
The function is not defined.
g(2) = 2/1-2
= 2/-1 = -2
The function is defined.
Therefore, we have found that the value of x for which the function g(x)=x/1-x is not defined is at x = 1.
Learn more about not defined functions here: https://brainly.com/question/12039003
#SPJ2