A) Acceleration in part A: [tex]6.1 m/s^2[/tex]
B) Acceleration in part B: [tex]2.7 m/s^2[/tex]
C) Acceleration in part C: [tex]1.5 m/s^2[/tex]
Explanation:
A)
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The acceleration of a body is equal to the rate of change of its velocity:
[tex]a=\frac{v-u}{\Delta t}[/tex]
where
v is the final velocity
u is the initial velocity
[tex]\Delta t[/tex] is the time it takes for the velocity to change from u to v
In part A of the race, we have:
u = 0
v = 5.5 m/s (estimate)
[tex]\Delta t = 0.9 - 0 = 0.9 s[/tex]
So the acceleration is
[tex]a=\frac{5.5-0}{0.9}=6.1 m/s^2[/tex]
B)
In part B of the race, we have:
u = 5.5 m/s is the initial velocity (estimate)
v = 9.5 m/s is the final velocity (estimate)
[tex]\Delta t = 2.4 - 0.9 = 1.5 s[/tex] is the time interval between the two points considered
Therefore, using the equation for the acceleration, we can find the acceleration in part B:
[tex]a=\frac{9.5-5.5}{1.5}=2.7 m/s^2[/tex]
C)
In part C of the race, we have:
u = 9.5 m/s is the initial velocity (estimate)
v = 11 m/s is the final velocity (estimate)
[tex]\Delta t = 3.4 - 2.4 = 1 s[/tex] is the time interval between the two points considered
And therefore, the acceleration in part C of the race is:
[tex]a=\frac{11-9.5}{1}=1.5 m/s^2[/tex]
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