Answer :
Step-by-step explanation:
The point-slope form of an equation of a line:
[tex]y-y_1=m(x-x_1)[/tex]
m - slope
(x₁, y₁) - point on a line
The formula of a slope:
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
We have the points (9, -2) and (4, 2).
Substitute:
[tex]m=\dfrac{2-(-2)}{4-9}=\dfrac{2+2}{-5}=-\dfrac{4}{5}[/tex]
Put the value of a slope and coordinates of first or second point to the equation of a line:
[tex](9,\ -2),\ m=-\dfrac{4}{5}\\\\y-(-2)=-\dfrac{4}{5}(x-9)\\\\\boxed{y+2=-\dfrac{4}{5}(x-9)}\\\\(4,\ 2),\ m=-\dfrac{4}{5}\\\\y-2=-\dfrac{4}{5}(x-4)}[/tex]