Answer :
Solving [tex]2\frac{1}{4}(4x-1)=1\frac{3}{5}(1+4x)[/tex] we get [tex]x=\frac{77}{52}[/tex]
Step-by-step explanation:
We need to solve the problem: [tex]2\frac{1}{4}(4x-1)=1\frac{3}{5}(1+4x)[/tex]
Solving:
[tex]2\frac{1}{4}(4x-1)=1\frac{3}{5}(1+4x)\\\frac{9}{4}(4x-1)=\frac{8}{5}(1+4x)\\9x-\frac{9}{4}=\frac{8}{5}+\frac{32x}{5}[/tex]
Add 9/4 on both sides:
[tex]9x-\frac{9}{4}+\frac{9}{4}=\frac{8}{5}+\frac{32x}{5}+\frac{9}{4}[/tex]
[tex]9x=\frac{8}{5}+\frac{9}{4}+\frac{32x}{5}\\9x-\frac{32x}{5}=\frac{8}{5}+\frac{9}{4}\\\frac{9x*5-32x}{5}=\frac{8*4+9*5}{20}\\\frac{45x-32x}{5}=\frac{32+45}{20}\\\frac{13x}{5}=\frac{77}{20}\\x=\frac{77}{20}\times \frac{5}{13}\\x=\frac{77}{4*13}\\x=\frac{77}{52}[/tex]
So, Solving [tex]2\frac{1}{4}(4x-1)=1\frac{3}{5}(1+4x)[/tex] we get [tex]x=\frac{77}{52}[/tex]
Keywords: Solving Fractions
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