Answer :
Step-by-step explanation:
[tex]f(x)=\dfrac{x^2-4x+2}{x+7}\\\\f(-1)=\text{put}\ x=-1\ \text{to}\ f(x):\\\\f(-1)=\dfrac{(-1)^2-4(-1)+2}{-1+7}=\dfrac{1+4+2}{6}=\dfrac{7}{6}[/tex]
Step-by-step explanation:
[tex]f(x)=\dfrac{x^2-4x+2}{x+7}\\\\f(-1)=\text{put}\ x=-1\ \text{to}\ f(x):\\\\f(-1)=\dfrac{(-1)^2-4(-1)+2}{-1+7}=\dfrac{1+4+2}{6}=\dfrac{7}{6}[/tex]