Answer:
[tex]y=3x+1[/tex]
Step-by-step explanation:
From the question, we are given;
- The equation y = 3x + 2
- A point (-1, -2)
We are required to determine the equation of a line parallel to the given line and passing through the point (-1, -2)
- We are going to determine the gradient of the line first; when an equation is written in the form of y = mx + c, where m is the gradient.
y = 3x + 2, m₁ = 3
- But, m₁ = m₂ for parallel lines
- Therefore, the gradient of the line in question, m₂ is 3
- With the gradient, m₂=3 , and a point (-1, -2) we can get its equation;
Taking another point (x, y)...
Then;
[tex]\frac{y+2}{x+1}=3[/tex]
[tex]y+2=3(x+1)\\y+2=3x+3\\y=3x+1[/tex]
Therefore; the equation of the line is [tex]y=3x+1[/tex]
