Answer :
Answer:
Yes, there is phase or position during the interaction of the two charges Q and 2 Q, that results in the electric field,E to be zero. And it is when the two charges are cancelling out each other effects by being at the opposite direction or position. As the electric field intensity or force, F will be equal to net zero in total.
Explanation:
As if the test charge is present a distance "d" away from the charge 2 Q, then the charge,Q will be more far from the test charge as it will be d-2 from the "Q" charges.
As we can do the calculations by the following procedure, as follow:
- K(2 Q/d)-K(Q/d-2)=0,
- Now, we can cancel out the common between the equations,
- K(2 Q/d)=K(Q/d-2),
- 2/d=1/d-2,
- Taking the square on both the sides,
- (2/d)²=(1)²/(d-2)²,
- 4/d²=1/d²+4 - 8 d²,
- 4(d²+4-8 d²)=d²,
- d²+1-2 d²=0,
