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The function S(D) =(7/2) √2D can be used to approximate the speed S, in miles per hour, of a car that has left skid marks of length D, in feet. How fast would would a car have been traveling if it left a skid mark that is 102.04 feet long?

Answer :

Answer:

If the car left a skid mark that is 102.04 feet long then the speed of the car would have been 505 feet/second.

Step-by-step explanation:

i) S(D) = 7/2 [tex]\sqrt{2} D[/tex]

ii) therefore S(102.04) = 3.5 [tex]\times[/tex] 1.414 [tex]\times[/tex] 102.04 = 505 feet/second.

iii) if the car left a skid mark that is 102.04 feet long then the speed of the car would have been 505 feet/second.

stoshpatel

Answer: The other answer is wrong. The answer would be about 50 miles per hour or 49.99 mph.

Step-by-step explanation:

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